Re: Problem - WeOnlyDo Discussion board

Re: Problem (General questions)

by celtik, Saturday, November 22, 2008, 17:36 (5846 days ago) @ celtik

Now, I have another project that uses listboxes so that it will go through the list checking each..Here is the code:

[code]
Dim strsplit() As String
Dim usernames(999) As String
Dim passwords(999) As String
Dim i As Integer

Command7.Enabled = True
blnGo = True

For i = 0 To List1.ListCount - 1
If blnGo = True Then

List1.ListIndex = i

If InStr(1, List1.Text, : ) = 0 Then
strsplit(0) =
strsplit(1) =
Label4.Caption = Bad Login!
Else
strsplit() = Split(List1.List(i), : )
usernames(i) = strsplit(0)
passwords(i) = strsplit(1)
End If

HTTP.URL = http://xxx
HTTP.Request.FormPost.Add _VIEWSTATE , 2FwEPDwUJNTU4OTgyNDc1ZBgBBR5fX0NvbnRyb2xzUmVxdWlyZVBvc3RCYWNrS2V5X18WAQUnY3RsMDAkY3BNYWluJExvZ2luQm94JFJlbWVtYmVyX0NoZWNrYm94
HTTP.Request.FormPost.Add NextPage ,
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$Email_Textbox , strsplit(0)
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$Password_Textbox , strsplit(1)
HTTP.Request.FormPost.Add dlb , Log In
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$SingleSignOnHash ,
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$SingleSignOnRequestUri ,
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$nexturl ,
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$apikey ,
HTTP.Request.FormPost.Add ctl00$cpMain$LoginBox$ContainerPage ,
HTTP.Post

If List1.ListCount - 1 = List1.ListIndex Then
Label4.Caption = Done!
End If
End If
Next i

Private Sub HTTP_Done(ByVal ErrorCode As Long, ByVal ErrorText As String)
Dim oldcookie As HttpCookie
For Each oldcookie In HTTP.Response.cookies
HTTP.Request.cookies.Add oldcookie.Name, oldcookie.Value
Next

If ErrorCode = 0 Then
HTTP.Disconnect
RichTextBox1.Text = HTTP.Response.Body
If InStr(1, RichTextBox1.Text, Skip this Advertisement ) Then
Label1.Caption = home
HTTP.Get http://xxxx
RichTextBox1.Text = HTTP.Response.Body
End If
If InStr(1, RichTextBox1.Text, My Friend Space ) Then
Label4.Caption = VALID
End If
If InStr(1, RichTextBox1.Text, Please log in to continue ) Then
Label4.Caption = INVALID
End If
Else
RichTextBox1.Text = ErrorText
End If
End Sub
[/code]

For some reason it says every account is invalid, which I do not understand.


Complete thread:

 

  • Problem - celtik, 2008-11-22, 17:34 [*]
    • Re: Problem - celtik, 2008-11-22, 17:36